Class 9 - Ganita Manjari Chapter 8 - Part 2
❮ PREV
NEXT ❯
Class 9 Ganita Manjari Chapter 8: Sequences and Progressions
Part 2
PREDICTING THE FUTURE Explicit Rules & Term Positions If the rule is: \(u_n = 2n - 1\) How do we find the 53rd term without writing 52 numbers? \(u_{53} = 2(53) - 1 = 105\) Explicit rules let you time travel to any position instantly!
[span_0](start_span)[span_0](end_span)[span_1](start_span)[span_1](end_span) To describe mathematical rules for sequences, we use notations like \(t_n, s_n,\) or \(u_n\) to represent the term at the \(n^{th}\) position. [span_2](start_span)[span_2](end_span)

An explicit rule uses the position number \(n\) to calculate the term's value directly. For example, if the formula is \(u_n = 2n - 1\), you can find the 100th term instantly by just substituting \(n = 100\), without ever needing to know the 99th term! [span_3](start_span)[span_3](end_span)[span_4](start_span)[span_4](end_span) Let's master explicit formulas.
1 Evaluating Explicit Rules
Ganita Manjari - Pg 177
Example 1 & Exercise: The explicit rule for the sequence of odd numbers is given by \(u_n = 2n - 1\). Using this formula, find the 53rd term, the 108th term, and the 1170th term of the sequence. [span_5](start_span)[span_5](end_span)
Concept:
1
An explicit rule is an algebraic formula that calculates any term directly based solely on its position number \((n)\). [span_6](start_span)[span_6](end_span)
2
We simply substitute the required position number for \(n\) in the formula to get the final value. [span_7](start_span)[span_7](end_span)
www.maheshkumarsir.in
Hint:
1
To find the 53rd term, set \(n = 53\).
2
Calculate: \(2(53) - 1\). [span_8](start_span)[span_8](end_span)
www.maheshkumarsir.in
Mistakes to Avoid:
!
Order of Operations (BODMAS): Always multiply the number by 2 first, and then subtract 1. Do not accidentally subtract 1 from \(n\) before multiplying!
www.maheshkumarsir.in
Solution:
Given the explicit rule: \(u_n = 2n - 1\)

1. Finding the 53rd term (\(n = 53\)):
\(u_{53} = 2(53) - 1\)
\(u_{53} = 106 - 1 =\) 105

2. Finding the 108th term (\(n = 108\)):
\(u_{108} = 2(108) - 1\)
\(u_{108} = 216 - 1 =\) 215

3. Finding the 1170th term (\(n = 1170\)):
\(u_{1170} = 2(1170) - 1\)
\(u_{1170} = 2340 - 1 =\) 2339
www.maheshkumarsir.in
2 Checking if a Number is a Term
Ganita Manjari - Pg 177
Example 2: Consider the sequence generated by the explicit formula \(s_n = 5n - 2\). Check if the numbers 308 and 471 are terms of this sequence. [span_9](start_span)[span_9](end_span)
Concept:
1
To check if a number belongs to a sequence, we set the explicit formula equal to that number and solve the algebraic equation for \(n\). [span_10](start_span)[span_10](end_span)
2
Because \(n\) represents a physical position (1st, 2nd, 3rd...), it MUST be a positive natural integer. If \(n\) turns out to be a decimal or fraction, the number is NOT in the sequence! [span_11](start_span)[span_11](end_span)
www.maheshkumarsir.in
Hint:
1
Set up the first equation: \(5n - 2 = 308\).
2
Set up the second equation: \(5n - 2 = 471\). [span_12](start_span)[span_12](end_span)
3
Solve for \(n\). Do both divide perfectly?
www.maheshkumarsir.in
Mistakes to Avoid:
!
Substituting the number for n: Do not calculate \(5(308) - 2\). The question asks if 308 is the result, not the position! We must solve backwards to find the position.
www.maheshkumarsir.in
Solution:
Given formula: \(s_n = 5n - 2\)

1. Checking 308:
Let \(s_n = 308\)
\(5n - 2 = 308\)
\(5n = 308 + 2\)
\(5n = 310\)
\(n = \frac{310}{5} = 62\)
Since 62 is a natural number, 308 is the 62nd term.

2. Checking 471:
Let \(s_n = 471\)
\(5n - 2 = 471\)
\(5n = 471 + 2\)
\(5n = 473\)
\(n = \frac{473}{5} = 94.6\)
Since 94.6 is a decimal (not a natural number), 471 is NOT a term.
www.maheshkumarsir.in
Select the correct option:
What is the primary advantage of having an explicit formula for a sequence? [span_13](start_span)[span_13](end_span)
Concept:
1
An explicit formula (like \(t_n = 2n + 1\)) is an independent equation. [span_14](start_span)[span_14](end_span)[span_15](start_span)[span_15](end_span)
www.maheshkumarsir.in
Hint:
1
If I want the 1,000,000th term, do I need to calculate the 999,999th term first? [span_16](start_span)[span_16](end_span)
www.maheshkumarsir.in
Mistakes to Avoid:
!
Confusing Explicit with Recursive: Option A describes a recursive formula, where you must know the previous step to take the next one.
www.maheshkumarsir.in
Solution:
As stated in the textbook, using an explicit formula, we can find the value of a term without having to know the value of previous terms. [span_17](start_span)[span_17](end_span)
www.maheshkumarsir.in
Select the correct option:
If a sequence is defined by the explicit rule \(t_n = 3n + 2\), what is the value of the 5th term?
Concept:
1
To find a specific term using an explicit rule, substitute the required position number for the variable \(n\). [span_18](start_span)[span_18](end_span)
www.maheshkumarsir.in
Hint:
1
Set \(n = 5\). Calculate \(3 \times 5 + 2\).
www.maheshkumarsir.in
Mistakes to Avoid:
!
Order of Operations error: If you calculate \(3 \times (5+2)\), you get 21. Multiplication must happen before addition!
www.maheshkumarsir.in
Solution:
Given: \(t_n = 3n + 2\)
For the 5th term, substitute \(n = 5\):
\(t_5 = 3(5) + 2\)
\(t_5 = 15 + 2 = 17\)
www.maheshkumarsir.in
Select the correct option:
In sequence notation, how is the first term of a sequence commonly represented? [span_19](start_span)[span_19](end_span)
Concept:
1
In sequence notation, the letter (like \(t, s, u\)) represents the sequence, and the small subscript number represents the position. [span_20](start_span)[span_20](end_span)
www.maheshkumarsir.in
Hint:
1
The first position uses the number 1.
www.maheshkumarsir.in
Mistakes to Avoid:
!
Starting at zero: Unlike some computer programming languages that start counting at 0, mathematical sequences almost always start at position 1. [span_21](start_span)[span_21](end_span)
www.maheshkumarsir.in
Solution:
As detailed in the textbook notation, we use \(t_1\) to represent the first term of a sequence, \(t_2\) for the second, and so on. [span_22](start_span)[span_22](end_span)
www.maheshkumarsir.in
Select the correct option:
When solving an equation to check if a number belongs to a sequence, why must the resulting value for n be a natural number? [span_23](start_span)[span_23](end_span)
Concept:
1
In sequence notation, \(n\) refers strictly to the index or position of a term. [span_24](start_span)[span_24](end_span)[span_25](start_span)[span_25](end_span)
www.maheshkumarsir.in
Hint:
1
Think of people standing in a line. You can have the 1st person, 2nd person, and 3rd person. Can you have the 2.5th person? [span_26](start_span)[span_26](end_span)
www.maheshkumarsir.in
Mistakes to Avoid:
!
Confusing the term value with the position: The term value can be anything (fraction, decimal, negative). But the position number (\(n\)) must always be a clean, positive integer (1, 2, 3...). [span_27](start_span)[span_27](end_span)
www.maheshkumarsir.in
Solution:
As noted in the textbook, \(n\) must be a non-negative natural integer because it represents the position in the sequence (1st, 2nd, 3rd). A position cannot be a fraction or a negative number. [span_28](start_span)[span_28](end_span)[span_29](start_span)[span_29](end_span)
www.maheshkumarsir.in
Select the correct option:
If a sequence has the explicit rule \(u_n = n^2 + 1\), what is the value of the 4th term?
Concept:
1
Explicit formulas can contain exponents. Substitute \(n\) carefully and follow order of operations (exponents before addition).
www.maheshkumarsir.in
Hint:
1
Set \(n = 4\).
2
Calculate \(4^2\), then add 1.
www.maheshkumarsir.in
Mistakes to Avoid:
!
Adding before squaring: If you calculate \((4+1)^2\), you will get \(5^2 = 25\), which is wrong.
www.maheshkumarsir.in
Solution:
Given: \(u_n = n^2 + 1\)
For the 4th term, substitute \(n = 4\):
\(u_4 = (4)^2 + 1\)
\(u_4 = 16 + 1 = 17\)
www.maheshkumarsir.in
★ Complex Explicit Formulas
Exemplar Challenge
A sequence is defined by the explicit formula \(a_n = n^2 + 1\).

Calculate the first three terms of this sequence. Then, determine if this sequence forms an Arithmetic Progression (AP). Justify your answer. [span_30](start_span)[span_30](end_span)
Concept:
1
A sequence is only an Arithmetic Progression (AP) if the difference between every consecutive term is exactly the same constant value. [span_31](start_span)[span_31](end_span)
www.maheshkumarsir.in
Hint:
1
Find \(a_1\), \(a_2\), and \(a_3\).
2
Subtract \(a_2 - a_1\). Then subtract \(a_3 - a_2\). Are those numbers identical? [span_32](start_span)[span_32](end_span)
www.maheshkumarsir.in
Mistakes to Avoid:
!
Assuming all formulas make APs: Explicit formulas can describe ANY pattern (squares, cubes, fractals). Only linear formulas (like \(3n+2\)) create Arithmetic Progressions. [span_33](start_span)[span_33](end_span)
www.maheshkumarsir.in
Solution:
Given formula: \(a_n = n^2 + 1\)
Let's find the first three terms:
\(a_1 = 1^2 + 1 = 2\)
\(a_2 = 2^2 + 1 = 5\)
\(a_3 = 3^2 + 1 = 10\)

Checking for a constant difference:
\(a_2 - a_1 = 5 - 2 = 3\)
\(a_3 - a_2 = 10 - 5 = 5\)
Since \(3 \neq 5\), the difference is not constant. [span_34](start_span)[span_34](end_span)

Ans: It does NOT form an AP.
www.maheshkumarsir.in
❮ PREV
NEXT ❯
πŸ“±⤿
Landscape Recommended
Rotate your phone to landscape mode for the best mathematical viewing experience!
×

Chapter 8: Sequences & Progressions

Part 1: Intro to Sequences & Patterns Ganita Manjari Pgs 174-175 Part 2: Explicit Rules & Predicting Terms Ganita Manjari Pgs 176-177 Part 3: Recursive Rules & Fibonacci Ganita Manjari Pgs 178-179 Part 4: Exercise 8.1 - Mastery (Q1-Q3) Ganita Manjari Pg 179 Part 5: Exercise 8.1 - Recursive (Q4-Q6) Ganita Manjari Pg 179-180 Part 6: Intro to AP & Common Difference Ganita Manjari Pgs 180-182 Part 7: AP Formulas & Taxi Fare Math Ganita Manjari Pgs 182-183 Part 8: Sum of First n Natural Numbers Ganita Manjari Pgs 183-185 Part 9: Exercise 8.2 - AP Basics (Q1-Q3) Ganita Manjari Pg 185 Part 10: Exercise 8.2 - Missing Terms (Q4-Q5) Ganita Manjari Pgs 185-186 Part 11: Exercise 8.2 - AP Word Problems Ganita Manjari Pg 186 Part 12: Intro to GP & Common Ratios Ganita Manjari Pgs 186-188 Part 13: Fun with Fractals: SierpiΕ„ski Ganita Manjari Pgs 188-190 Part 14: GP Graphs & Bouncing Balls Ganita Manjari Pgs 190-193 Part 15: Exercise 8.3 - GP Basics Ganita Manjari Pg 193 Part 16: Exercise 8.3 - Rebounds & Roots Ganita Manjari Pgs 193-194 Part 17: Exercise 8.3 - SierpiΕ„ski Carpet Ganita Manjari Pg 194 Part 18: End of Chapter - AP Logic Ganita Manjari Pgs 194-195 Part 19: End of Chapter - Divisibility Ganita Manjari Pg 195 Part 20: End of Chapter - Consecutive Sums Ganita Manjari Pg 195 Part 21: End of Chapter - Dual Equations Ganita Manjari Pg 195 Part 22: End of Chapter - GP Proofs Ganita Manjari Pg 195 Part 23: End of Chapter - Complex Logic Ganita Manjari Pg 195 Part 24: End of Chapter - Recursive Chains Ganita Manjari Pg 195 Part 25: Chapter Summary & Finale Ganita Manjari Pg 196
Celebrating Academic Brilliance

Celebrating Academic Brilliance

We are proud to honor our outstanding achievers who have set remarkable benchmarks in the CBSE Board examinations.

100 Asawari Nimbalkar
100 Apurva Chame
100 Aarya Itkar
100 Kevali Pangal
100 Shivam Vishwekar
99 Satyajit Todkar
99 Vedika Jamadar
99 Sandesh Jadhavar
99 Aarya Kasarkhedkar
99 Omkeshwar Singh
98 Shreenath Rathi
98 Dhruv Somani
98 Janhavi Bandgar
98 Akshat Darak
98 Atharv Amle
97 Ganesh Nimbalkar
97 Aditya Bajaj
97 Atharv Narache
97 Atharv Mundada
97 Shrived Dudhani
96 Neel Mantri
96 Siddhi Bhutada
96 Vedant Jadhav
95 Arpita Bharadiya
95 Vidya Singh
95 Anshita Rajure
95 Samarth Abhange
95 Sarthak Shelke
95 Varad Bang
Celebrating Excellence
Examinations

πŸŽ‰ Celebrating Excellence:
Our Stars Shine Bright in CBSE 2026! 🌟

At Mind Square Maths Classes, success is not just a goal—it’s a tradition. ✨

100
Harshwardhan Dilip Tambare
(Renaissance CBSE School, Latur)
100
Ishan Mithun Tapadiya
(Raja Narayanlal Lahoti English School)
99
Sairaj Satyanarayan Kacholiya
(Sant Tukaram National Model School, Latur)
99
Netal Purushottam Soni
(Raja Narayanlal Lahoti English School)
99
Swara Amit Itkar
(Raja Narayanlal Lahoti English School)
πŸ‘ Your dedication, discipline, and hard work have truly paid off.
Keep striving for excellence and reaching new heights! πŸš€

What Our Students & Parents Say

With a perfect 5.0 Rating, here is how Maheshkumar Sir is changing the way students approach mathematics.

Ms. Aarya Itkar
★★★★★
WhatsApp Message
18 June

"Thank you so much sir!! We'll be forever grateful for your efforts and motivation!! Wishing you and m2 education loads of success!! Thank you πŸ˜ŠπŸ™"

Ms. Swara Itkar
★★★★★
WhatsApp Message
18 March

"Hare krishna sir πŸ™ Swara here Aaj ka paper aacha gya sir ..apne revision mai jo question liye the vahi sab aaye the πŸ™πŸ™"

Ms. Anshita Rajure
★★★★★
WhatsApp Message
5 September

"Thank you for your guidance and help. No one else can teach this subject as well as you do. Missing your lectures a lot πŸ˜ŠπŸ™"

Ms. Vedika Jamadar
★★★★★
WhatsApp Message
9 October

"A teacher like you has so many great qualities, but one in particular that I respect the most is your patience. You always have time for your students and you never give up on them. You truly are as committed as you are wonderful... HARE KRISHNA"

Ajit Nimbalkar
★★★★★
WhatsApp Message
10 June

"Thankyou Sir, For becoming the first Guru of my daughter and making her successful results in her board exam."

Arnabh Deo
★★★★★
Google Review
a year ago

"Mahesh Sir is one of the finest Mathematics teachers in Latur City, He easily and in a very sophisticated manner explains hardest of the problems. Fun Fact: I was able to crack my Tenth boards due to Sir's exemplary teaching."

Kevali Pangal
★★★★★
Google Review
a year ago

"Maheshkumar sir is one of the best teacher I have studied from. His way of teaching is so nice and is easily understandable. I have been his student for 4 years, and throughout these years he was always there to guide me."

Firos Sayyed
★★★★★
Google Review
11 months ago

"Sir's teaching skills are just mind blowing giving attention to all students equally and concentrating more on average and below average students constantly keeping extra classes for them and even calling them in extra time for their revision."

Gandharv Chamale
★★★★★
Google Review
a year ago

"Maheshkumar sir always helps student when they have doubts and gives special attention to each and every student and encourages them. From 2 years, my child getting improving in maths. After every tuition exam, he analysis the paper."

Hemali Shah
★★★★★
Google Review
11 months ago

"Mind square class provides excellence teaching with clear explanation and help us to understand our potential. Mahesh sir is very supportive, and the environment is motivating and positive. It's a great place to learn and grow with the best surrounding."

Shrikant Itkar
★★★★★
Google Review
9 months ago

"Since the first day, the teaching methods of Maheshkumar sir have made maths much clearer and interesting for me. I'm really enjoying the learning at Mind Square. Thank you Sir for helping and guiding me. Hare Krishna πŸ™"

Alfez Gidde
★★★★★
Google Review
11 months ago

"A kind hearted personality of our maheshkumar sir and style of teaching like a friend touches our heart like a tangent. We are lucky to get such a friend like teacher."

Sonia Agarwal
★★★★★
Google Review
a year ago

"Maheshkumar Sir is an excellent Maths teacher who explains concepts with great clarity and patience. His way of teaching makes even difficult topics easy to understand, and he always encourages students to ask doubts."

Kedar Meru
★★★★★
Google Review
11 months ago

"I’ve had an excellent experience with these maths coaching classes. The concepts are explained clearly, and difficult topics are broken down in a way that’s easy to understand. The teachers are patient, approachable."

Janabai Bhosale
★★★★★
Google Review
a year ago

"I’ve had an excellent experience at this maths tuition! The teaching style is very clear and easy to understand, even for the toughest concepts. Each topic is explained step by step with real-life examples."

Sharayu Bajaj
★★★★★
Google Review
a year ago

"Math classes have been really helpful. The teacher explains every concept clearly and makes sure we understand before moving ahead. I feel much more confident in solving problems now."

Siddhi Todkar
★★★★★
Google Review
9 months ago

"I am having the best experience of learning since I've joined mind square.. Maheshkumar sir made be believe and know the potential I have.. Thank you sir πŸ™πŸ™"

Varsha Mandhana
★★★★★
Google Review
11 months ago

"One of the best maths teachers! Sir teaches with clarity, patience, and always encourages us to do better. Sir had made maths more easier!"

Aparna Mundada
★★★★★
Google Review
a year ago

"Thank you for making mathematics clear, engaging, and enjoyable. Your passion, patience, and dedication have truly inspired me. I’m grateful to have learned from the best!"

Gopal Mundada
★★★★★
Google Review
a year ago

"The way you teach maths makes it so easy to understand. You explain clearly, give real examples, and never get tired of our doubts. You make maths feel simple and even enjoyable. Thank You Sir For Your Efforts."

Nita Bidada
★★★★★
Google Review
a year ago

"Mahesh Kumar sir is one of the best teacher. I was not able to understand but when I joined Mind² then I am able to understand the maths and the concept of the maths. And they personally gives attention towards me."

Balaji Dahire
★★★★★
Google Review
a year ago

"You're an innovative and creative personπŸ‘πŸ». I am very glad to have a hardworking teacher for my child. As i noticed my child is having more interest in maths as before she was hating this subject and even doing the self study."

Vanshika Ghule
★★★★★
Google Review
3 weeks ago

"Sir teaches very nice and has experience of teching. For maths it is best tution in latur."

Gauravi Lamdade
★★★★★
Google Review
2 months ago

"Excellent classes !! Sir explain everything in very easy way... Very helpful for me."

Gauravi Bidada
★★★★★
Google Review
11 months ago

"Your passion for the maths made our lessons engaging and the way you explain all the topics. I appreciate the positivity and supportive environment you create in class. Thank-you sir for your best teaching πŸ™πŸ˜Š"

Avanti Ausekar
★★★★★
Google Review
3 weeks ago

"Very good quality of education with constant tests and revisions of chapters"

Rupali Dabhade
★★★★★
Google Review
a year ago

"Mahesh Kumar sir always give a potential and motivation to every student. They are the best teacher of maths . They teach every concept neatly and clearly. Excellent and cooperative teacher πŸ™πŸ’"

VΓ€RDHAΓ‘ Mundada
★★★★★
Google Review
9 months ago

"Mahesh Kumar sir is the best teacher. His way of teaching and way of solving math questions is the best thank you sir for devoleping my math skills. you are the best sir"

Swati Dhoot
★★★★★
Google Review
9 months ago

"Mahesh Kumar Sir is the strength of M2 Classes, guiding students with knowledge and dedication."

Poonam Mundada
★★★★★
Google Review
9 months ago

"One of the best teacher in my life!sir teaches with concepts clearance, patience, understanding way and in simple way. There is very good learning environment."

MADHUR TAPDIYA
★★★★★
Google Review
9 months ago

"The joyoud and entertaining way of learning from maheshkumar sir and the brilliant way of learning can make that one to fall in love with mathematics who hates it most .....!"

Farha Ustad
★★★★★
Google Review
9 months ago

"This tution is one of the best tutions, the teacher respected maheshkumar sir make toughest of the topics understandable and easy. It has helped me a lot improve in my studies"

Seema itkar
★★★★★
Google Review
9 months ago

"I am having great learning at mind sqaure. The supportive environment and effective teaching really makes me improve my confidence and Understanding."

Mayuresh chintalwar
★★★★★
Google Review
a year ago

"I am studying her from my 8th and I have a very good experience about the teaching of sir and I am even scoring very well in my exams πŸ‘"

Mind Square Admissions